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Using Spark to create a new account "a c" will create a user "a\20c" in the database. => Fine
Spark will then display "a\20c" as the login name which is wrong, changing it to "a c" will allow one to login.
Fix this so Spark will display the un-escaped name.
Mass closing of resolved issues
Using Spark to create a new account "a c" will create a user "a\20c" in the database. => Fine
Spark will then display "a\20c" as the login name which is wrong, changing it to "a c" will allow one to login.
Fix this so Spark will display the un-escaped name.